By M. J. Economides
This workbook is a realistic better half to the second one variation of the textbook Reservoir Stimulation. the 2 books are meant for use jointly. This new quantity could be relatively helpful for the learning of latest engineers and petroleum engineering scholars, because it includes nearly a hundred difficulties and their options, plus a long bankruptcy giving information beneficial for designing a stimulation remedy. Chapters are integrated containing functional difficulties on reservoir and good concerns, rock mechanics, fracturing fluids and proppants, fracture calibration remedies, layout and modeling of propped fractures, review of fracture remedies, layout of matrix remedies, diversion and therapy assessment, layout and function of acid fractures and stimulation of horizontal wells. those chapters are categorized with letters from A to J to tell apart them from their spouse chapters in Reservoir Stimulation. Equations, figures and tables from the textbook are pointed out within the workbook yet will not be reproduced.
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Extra info for A Practical Companion to Reservoir Stimulation
D-6 penetration and net pressure for FRACTURE CALIBRATION TREATMENTS EXAMPLE D-5 EXAMPLE D-6 Calculation of Distance to Restricted Fracture Comparison of Fluid Loss During Pumping and During Closure Assume that after 30 min of pumping the pressure starts increasing at 200 psi/min. If E’ = 3 x lo6 psi, q i= 40 BPM and h = 50 ft, calculate the maximum distance to the point of restricted fracture. Solution (Ref. 3) Since dpJdt = m = 200 psi/min, then from Eq. 2E%, If the pumping time and the closure time is the same (30 min), calculate the total fluid lost during pumping and closure.
C, Since no information was given on reservoir pressure, then c, = 10-5psi +3x (B-9) Table B-1-Formation data for Example B-2. B-3 PRACTICAL COMPANION T O RESERVOIR STIMULATION EXAMPLE B-3 EXAMPLE B-4 Calculation of Horizontal Stresses Critical Depth for Horizontal vs. Vertical Hydraulic Fractures Calculate the minimum horizontal stress at 10,000 ft depth for a formation with the properties used in Example B-2. 25. Will the absolute minimum stress increase or decrease during reservoir depletion?
Assuming that the Poisson’s relationship is in effect and assuming that the horizontal stresses are ‘‘locked’’in place, what would be the critical depth above which horizontal fractures would be generated if 2000 ft of overburden were removed by some geologic means? Use the formation variables given in Example B-2. Solution (Ref. 1) Equation 2-41 a provides the absolute minimum horizontal stress as a function of the vertical stress. The vertical stress is equal to the weight of the overburden. Furthermore, the pore pressure was assumed to be the hydrostatic value.